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2x=3(1-x)-(x+1) ~x等如咩??

發問:

2x=3(1-x)-(x+1) x等如咩?? ~ 10點 更新: 2. 6[2(2-y)-3y]=24 2-t 2t-3 3. ------- - t = ---------- 4 5 4. 9(2a-1)=3[4(1+2a)-5]-8a 5. 1/3(t+9)=1/3-0.5(t+3) 6. 28y=2[16-4(1-y)] 更新 2: 3 2-t 2t-3 ------ -- t = ---------- 4 5 更新 3: 3. (2-t)/4 -t = (2t-3)/5

最佳解答:

1] 2x=3(1-x)-(x+1) 2x=3-3x-x-1 2x=2-4x 2x+4x=2 6x=2 x=2/6 x=1/3 2] 6[2(2-y)-3y]=24 6[4-2y-3y]=24 6[4-5y]=24 24-30y=24 24-24=30y 0=30y y=0/30 y=0 3] (2-t)/4 -t = (2t-3)/5 5[(2-t)/4 –t] = 2t-3 (10-5t)/20 –t = 2t-3 (10-5t)/20 = 2t-3-t (10-5t)/20 = t-3 10-5t = 20(t-3) 10-5t = 20t-60 10+60 = 20t+5t 70 = 25t t = 70/25 t = 2.8 4] 9(2a-1)=3[4(1+2a)-5]-8a 18a-9=3[4+8a-5]-8a 18a-9=3[8a-1]-8a 18a-9=24a-3-8a 18a-24a+8a=-3+9 2a=6 a=6/2 a=3 5] 1/3(t+9)=1/3-0.5(t+3) [1/3(t+9)]{3-0.5(t+3)}=1 [3-0.5(t+3)]/3(t+9)=1 3-0.5(t+3)=3(t+9) 3-0.5t-1.5=3t+27 3-1.5-27=3t+0.5t -25.5=3.5t t=-25.5/3.5 t=-7.285714285 6] 28y=2[16-4(1-y)] 28y=2[16-4+4y] 28y=2[12+4y] 28y=24+8y 28y-8y=24 20y=24 y=24/20 y=1.2

其他解答:

2x=3(1-x)-(x+1) 2x = 3 - 3x - x - 1 2x = -4x + 2 6x = 2 x = 1/3 2009-02-11 13:02:03 補充： [2] 6[2(2-y)-3y]=24 12(2-y) - 18y = 24 24 - 12y - 18y = 24 y = 0 [3]乜??????????? [4] 9(2a-1)=3[4(1+2a)-5]-8a 18a - 9 = 12(1+2a)-15 - 8a 26a + 6 = 12 + 24a 2a = 6 a = 3 [5A] (我可能誤會左) 1/3(t+9)=1/3-0.5(t+3) 1/(t+9) = 1 - 1.5(t+3) 1 = t+9 - 1.5(t^2+12t+27) 1.5t^2 + 20.5t + 31.5 = 0 t = -1.76(2sf) or t = -11.90 (2sf) 2009-02-11 13:02:06 補充： [5B] (我估你想講呢個) 1/3(t+9)=1/3-0.5(t+3) t+9 = 1 - 1.5(t+3) t + 8 = -1.5t - 4.5 2.5t = -12.5 t = -5 [6] 28y=2[16-4(1-y)] 28y = 32 - 8(1-y) 28y = 32 - 8 + 8y 20y = 24 y = 6/5 (or 1.2) 2009-02-12 03:27:12 補充： [3] (2-t)/4 -t = (2t-3)/5 5(2-t) - 20t = 4(2t-3) 10 - 5t - 20t = 8t - 12 22 = 33t t = 2/3