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標題:

Binomial Thm.

發問:

Find the constant term in the expansion : (x - 2/x^2)^3(3x + 1/x)^4

最佳解答:

Degree of each term of (x-2/x^2)^3: 3,0,-3,-6 Degree of each term of (3x+1/x)^4: 4,2,0,-2,-4 Therefore it is trivial that there is only 1 constant term in the expansion of(x-2/x^2)^3(3x+1/x)^4: 3 * [x^2 * (-2/x^2)] * 6 * [(3x)^2 * (1/x)^2] =3 * -2x^2/x^2 * 6 * 9x^2/x^2 =3 * -2 * 6 * 9 =-324 2013-06-16 08:24:37 補充： Feel free to ask me for further questions.

其他解答:

Find the constant term in the expansion : (x－2/x^2)^3(3x+1/x)^4 Sol (x－2/x^2)^3(3x+1/x)^4 =(x^3－2)^3(3x^2+1)^4/x^10 10=6+4 C(3，2)*(－2)*C(4，2)*3^2 =3*(－2)*6*9 =－324A9A39959EDCC7BE3