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Keq for a Gas-Phase Reaction
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Keq for a Gas-Phase ReactionA 7.00-L vessel contained 9.08×10-2 mol of gaseous PCl3, 1.02×10-1 mol of gaseous PCl5, and 1.02×10-1 mol of Cl2 gas at equilibrium at 223°C. Calculate the value of Keq (expressed in terms of the molar concentrations) for the reactionPCl3(g) + Cl2(g)... 顯示更多 Keq for a Gas-Phase Reaction A 7.00-L vessel contained 9.08×10-2 mol of gaseous PCl3, 1.02×10-1 mol of gaseous PCl5, and 1.02×10-1 mol of Cl2 gas at equilibrium at 223°C. Calculate the value of Keq (expressed in terms of the molar concentrations) for the reactionPCl3(g) + Cl2(g) 圖片參考：https://lewis.chem.sfu.ca/res/sfu/batchelo/Gallery/rlharpoons.gif PCl5(g)
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A 7.00-L vesselcontained 9.08 × 10?2 mol of gaseous PCl3, 1.02 × 10?1 mol ofgaseous PCl5, and 1.02 × 10?1 mol of Cl2 gas atequilibrium at 223°C. Calculate the value of Keq (expressed in terms of the molarconcentrations) for the reaction PCl3(g) + Cl2(g) ? PCl5(g) Solution : [PCl3] = (9.08 × 10?2)/7.00 = 0.0908/7 mol/L [PCl5] = [Cl2] = (1.02 x 10?1)/7.00 = 0.102/7 mol/L Keq = [PCl5]/([PCl3] x [Cl2]) = 1/[PCl3]= 1/(0.0908/7) = 77.1 (mol/L)?1
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